We are in Beta and we are offering 50% off! Use code BETATESTER at checkout.
You can access a significantly larger sample of the platform's content for free by logging in with your Gmail account. Sign in now to explore.

Sample Ratio Mismatch

A/B Testing Medium Seen in real interview

What are some reasons that can cause Sample Ratio Mismatch (SRM)? How do you test for SRM?

First let’s recall what is SRM:

Sample ratio mismatch (SRM) occurs when the ratio of observations between control and treatment is not close to the designed (expected) ratio. SRM suggests that something in the experiment is not working as it should (randomization did not work properly), and hence it threatens the experiment’s internal validity (p.45, Kohavi, Tang, and Xu (2020)).


Some of the reasons that SRM can happen include:

  • Page redirects for treatment (e.g., the treatment is implemented through web page redirects that take significantly longer)

  • Bad hash randomization (more generally buggy code of randomization)

  • If the conditions for treatment triggering are influenced by the experiment (more generally, bad trigger conditions can lead to imbalance)

  • Data pipeline logging, e.g. removing users who are inactivated or deemed bots

  • Time of day treatment occurs for test and control can bias metric measurement

We can test for SRM through a chi-squared test, where the null is that the SR = 1. Consider for instance that we split 1000 users evenly but the actual groups are 550 - 450. We can estimate the \(\chi^2\) statistic as follows:

\[ \chi^2 = \sum_i \frac{(O_i - N p_i)^2}{Np_i} = \frac{(550-500)^2 + (450-500)^2}{500} = 10 \] The value of the \(\chi^2\) statistic is too large for it to have come from the Null, and hence we can reject the Null.

from scipy.stats import chisquare
observed = [550,450]
expected = [500,500]
chi = chisquare(observed, f_exp=expected)
print(f"chi squared statistic: {chi[0]} \np-val: {chi[1]:.3f}")
## chi squared statistic: 10.0 
## p-val: 0.002



Topics

Sample Ratio Mismatch
Similar questions

Provide feedback